32^x=(1/128)^x-4

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Solution for 32^x=(1/128)^x-4 equation: 



32^x=(1/128)^x-4

We move all terms to the left:

32^x-((1/128)^x-4)=0



Domain of the equation: 128)^x-4)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

32^x-((+1/128)^x-4)=0

We multiply all the terms by the denominator


32^x*128)^x-4)-((+1=0

Wy multiply elements

4096x^2+1=0

a = 4096; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·4096·1
Δ = -16384
Delta is less than zero, so there is no solution for the equation

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